Create a class phone having data members: 1. The STD code 2. The Exchange code 3. Phone Number Ex :- 212-766-8901 Write a C++ program to accept details from user (max 10) and change input phone number to new phone number using following criteria: a) Add 1 to 1st digit of STD code. (If digit is 9 it becomes 10) b) The exchange code is retained as it is. c) In 3rd part of structure, 1st two digits should be reversed. Ex: I/P : 212-766-890 => O/P : 312-766-980 Display all changed phone numbers.

#include<iostream.h>
#include<stdlib.h>
#include<conio.h>
#include<string.h>
class phone
{
int p,c,s,ph[4],std[3];
public:
void accept();
void display();
void new_ph();
};

void phone::accept()
{
cout<<"Enter STD no.:\t";
cin>>s;
cout<<"\n\nEnter Exchange code : ";
cin>>c;
cout<<"\n\nEnter phone number : ";
cin>>p;
cout<<"\n\nOld Phone Number is   : ";
cout<<s<<"-"<<c<<"-"<<p;

}

void phone::display()
{
for(int i=0;i<=2;i++)
cout<<std[i];
cout<<"-";
cout<<c;
cout<<"-";
for(i=0;i<=2;i++)
cout<<ph[i];
}

void phone::new_ph()
{
int i=2,k=0;
while(s>0)
{
k=s%10;
std[i]=k;
s=s/10;
i--;
}
i=2,k=0;
while(p>0)
{
k=p%10;
ph[i]=k;
p=p/10;
i--;
}
std[2]=std[2]+1;
int tmp;
tmp=ph[0];
ph[0]=ph[1];
ph[1]=tmp;
}


int main()
{
clrscr();
phone p;
p.accept();
p.new_ph();
cout<<"\n\nNew Phone  Number is  : ";
p.display();
getch();
return 0;
}